To prove that triangles \( \triangle ABC \cong \triangle EDC \) using the Side-Angle-Side (SAS) congruence criterion, we need to establish the following:
- One pair of sides must be congruent.
- The included angle between those two sides must be congruent.
- Another pair of sides must be congruent.
Given that point \( C \) is the midpoint of \( \overline{BD} \) and \( \overline{AE} \), we know that:
- \( \overline{BC} \cong \overline{CD} \) (since \( C \) is the midpoint of \( \overline{BD} \)).
- \( \overline{AC} \cong \overline{CE} \) (since \( C \) is the midpoint of \( \overline{AE} \)).
Thus, we already have two pairs of congruent sides: \( \overline{BC} \cong \overline{DC} \) and \( \overline{AC} \cong \overline{ED} \), but we still need the included angle to be congruent.
Among the provided options, the correct additional information needed is:
∠ACB ≅ ∠ECD
This choice gives us the included angle between the two pairs of congruent sides \( \overline{AB} \) and \( \overline{ED} \), along with the side \( \overline{AC} \) and \( \overline{EC} \) to prove that \( \triangle ABC \cong \triangle EDC \) by SAS.
Summary:
The correct response is ∠ACB ≅ ∠ECD, because it provides the necessary angle needed to apply the SAS criterion for triangle congruence.