Asked by KaZi_Ek1A

can you rewrite it without abbreviations

Answers

Answered by KaZi_Ek1A
### Step 1: Isolate the Exponential Term
- Start with the equation:
\[
3.5 \cdot 1.2^x = 5.4
\]
- Divide both sides by :
\[
1.2^x = \frac{5.4}{3.5}
\]

### Step 2: Simplify the Right Side
- Calculate :
\[
1.2^x = 1.542857 \quad (\text{approximately})
\]

### Step 3: Take the Logarithm
- Apply logarithm to both sides (we can use common logarithm  or natural logarithm ):
\[
\log(1.2^x) = \log(1.542857)
\]

### Step 4: Use the Power Rule
- Using the power rule :
\[
x \cdot \log(1.2) = \log(1.542857)
\]

### Step 5: Solve for 
- Rearrange to solve for :
\[
x = \frac{\log(1.542857)}{\log(1.2)}
\]

### Step 6: Calculate the Values
- Use a calculator to find the logarithmic values and compute :
- 
- 

Using these values:
\[
x \approx \frac{0.187}{0.079} \approx 2.37 \quad (\text{approximately})
\]

### Final Answer
Thus, the solution is:
\[
x \approx 2.37
\]
Answered by KaZi_Ek1A
### Step 1: Isolate the Exponential Term- Start with the equation:\[3.5 \cdot 1.2^x = 5.4\]- Divide both sides by [lrnwysimath]\( 3.5 \)[/lrnwysimath]:\[1.2^x = \frac{5.4}{3.5}\]### Step 2: Simplify the Right Side- Calculate [lrnwysimath]\( \frac{5.4}{3.5} \)[/lrnwysimath]:\[1.2^x = 1.542857 \quad (\text{approximately})\]### Step 3: Take the Logarithm- Apply logarithm to both sides (we can use common logarithm [lrnwysimath]\( \log \)[/lrnwysimath] or natural logarithm [lrnwysimath]\( \ln \)[/lrnwysimath]):\[\log(1.2^x) = \log(1.542857)\]### Step 4: Use the Power Rule- Using the power rule [lrnwysimath]\( \log(a^b) = b \cdot \log(a) \)[/lrnwysimath]:\[x \cdot \log(1.2) = \log(1.542857)\]### Step 5: Solve for [lrnwysimath]\( x \)[/lrnwysimath]- Rearrange to solve for [lrnwysimath]\( x \)[/lrnwysimath]:\[x = \frac{\log(1.542857)}{\log(1.2)}\]### Step 6: Calculate the Values- Use a calculator to find the logarithmic values and compute [lrnwysimath]\( x \)[/lrnwysimath]:- [lrnwysimath]\( \log(1.542857) \approx 0.187 \)[/lrnwysimath]- [lrnwysimath]\( \log(1.2) \approx 0.079 \)[/lrnwysimath]Using these values:\[x \approx \frac{0.187}{0.079} \approx 2.37 \quad (\text{approximately})\]### Final AnswerThus, the solution is:\[x \approx 2.37\]
Answered by KaZi_Ek1A
can you write it without shortening the words
Answered by KaZi_Ek1A
Can you write that without saying /cdot, /frac, or /approx?
Answered by GPT-4o mini
Of course! Please provide the text that you would like me to rewrite without abbreviations.
Answered by GPT-4o mini
Certainly! Here is the rewritten text without abbreviations:

### Step 1: Isolate the Exponential Term
- Start with the equation:
\[
3.5 \cdot 1.2^x = 5.4
\]
- Divide both sides by three point five:
\[
1.2^x = \frac{5.4}{3.5}
\]

### Step 2: Simplify the Right Side
- Calculate the right side:
\[
1.2^x = 1.542857 \quad (\text{approximately})
\]

### Step 3: Take the Logarithm
- Apply logarithm to both sides (we can use the common logarithm or the natural logarithm):
\[
\log(1.2^x) = \log(1.542857)
\]

### Step 4: Use the Power Rule
- Using the power rule:
\[
x \cdot \log(1.2) = \log(1.542857)
\]

### Step 5: Solve for \( x \)
- Rearrange to solve for \( x \):
\[
x = \frac{\log(1.542857)}{\log(1.2)}
\]

### Step 6: Calculate the Values
- Use a calculator to find the logarithmic values and compute \( x \):
- \( \log(1.542857) \)
- \( \log(1.2) \)

Using these values:
\[
x \approx \frac{0.187}{0.079} \approx 2.37 \quad (\text{approximately})
\]

### Final Answer
Thus, the solution is:
\[
x \approx 2.37
\]
Answered by GPT-4o mini
Sure! Here is the rewritten text without abbreviations, while maintaining clarity and detail:

### Step 1: Isolate the Exponential Term
- Start with the equation:
\[
3.5 \cdot 1.2^x = 5.4
\]
- Divide both sides by three point five:
\[
1.2^x = \frac{5.4}{3.5}
\]

### Step 2: Simplify the Right Side
- Calculate the value of \(\frac{5.4}{3.5}\):
\[
1.2^x = 1.542857 \quad (\text{approximately})
\]

### Step 3: Take the Logarithm
- Apply logarithm to both sides (we can use the common logarithm or the natural logarithm):
\[
\log(1.2^x) = \log(1.542857)
\]

### Step 4: Use the Power Rule
- Using the power rule, which states that \(\log(a^b) = b \cdot \log(a)\):
\[
x \cdot \log(1.2) = \log(1.542857)
\]

### Step 5: Solve for \( x \)
- Rearrange the equation to solve for \( x \):
\[
x = \frac{\log(1.542857)}{\log(1.2)}
\]

### Step 6: Calculate the Values
- Use a calculator to find the logarithmic values and compute \( x \):
- \( \log(1.542857) \approx 0.187 \)
- \( \log(1.2) \approx 0.079 \)

Using these values:
\[
x \approx \frac{0.187}{0.079} \approx 2.37 \quad (\text{approximately})
\]

### Final Answer
Thus, the solution is:
\[
x \approx 2.37
\]
Answered by GPT-4o mini
Certainly! Here is the text rewritten without any shortened words or abbreviations:

### Step 1: Isolate the Exponential Term
- Begin with the equation:
\[
3.5 \cdot 1.2^x = 5.4
\]
- Divide both sides by three point five:
\[
1.2^x = \frac{5.4}{3.5}
\]

### Step 2: Simplify the Right Side
- Calculate the value of the fraction, five point four divided by three point five:
\[
1.2^x = 1.542857 \quad (\text{approximately})
\]

### Step 3: Take the Logarithm
- Apply the logarithm to both sides (one may use the common logarithm or the natural logarithm):
\[
\log(1.2^x) = \log(1.542857)
\]

### Step 4: Use the Power Rule
- Using the power rule, which states that the logarithm of a number raised to a power is equal to the power multiplied by the logarithm of the base:
\[
x \cdot \log(1.2) = \log(1.542857)
\]

### Step 5: Solve for \( x \)
- Rearrange the equation to solve for the variable \( x \):
\[
x = \frac{\log(1.542857)}{\log(1.2)}
\]

### Step 6: Calculate the Values
- Use a calculator to find the logarithmic values and compute \( x \):
- The logarithm of one point five four two eight five seven is approximately zero point one eight seven.
- The logarithm of one point two is approximately zero point zero seven nine.

Using these values:
\[
x \approx \frac{0.187}{0.079} \approx 2.37 \quad (\text{approximately})
\]

### Final Answer
Thus, the solution is:
\[
x \approx 2.37
\]
Answered by GPT-4o mini
Certainly! Here is the text rewritten without using the terms for multiplication, division, or approximation:

### Step 1: Isolate the Exponential Term
- Begin with the equation:
\[
3.5 times 1.2 raised to the power of x equals 5.4
\]
- Divide both sides by three point five:
\[
1.2 raised to the power of x equals five point four divided by three point five
\]

### Step 2: Simplify the Right Side
- Calculate the value of the fraction, five point four divided by three point five:
\[
1.2 raised to the power of x equals approximately one point five four two eight five seven
\]

### Step 3: Take the Logarithm
- Apply the logarithm to both sides (one may use the common logarithm or the natural logarithm):
\[
log(1.2 raised to the power of x) equals log(1.542857)
\]

### Step 4: Use the Power Rule
- Using the power rule, which states that the logarithm of a number raised to a power is equal to the power multiplied by the logarithm of the base:
\[
x times log(1.2) equals log(1.542857)
\]

### Step 5: Solve for x
- Rearrange the equation to solve for the variable x:
\[
x equals log(1.542857) divided by log(1.2)
\]

### Step 6: Calculate the Values
- Use a calculator to find the logarithmic values and compute x:
- The logarithm of one point five four two eight five seven is approximately zero point one eight seven.
- The logarithm of one point two is approximately zero point zero seven nine.

Using these values:
\[
x is approximately equal to zero point one eight seven divided by zero point zero seven nine, which is approximately two point three seven
\]

### Final Answer
Thus, the solution is:
\[
x is approximately equal to two point three seven
\]

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