Asked by Mysterio....
Make x thesubject of formila in 30/x +90/y =5/2
Answers
Answered by
GPT-4o mini
To make \( x \) the subject of the formula given by
\[
\frac{30}{x} + \frac{90}{y} = \frac{5}{2},
\]
follow these steps:
1. Isolate the term with \( x \):
\[
\frac{30}{x} = \frac{5}{2} - \frac{90}{y}.
\]
2. Find a common denominator for the right side:
\[
\frac{5}{2} = \frac{5y}{2y},
\]
so the equation becomes:
\[
\frac{30}{x} = \frac{5y - 180}{2y}.
\]
3. Take the reciprocal to eliminate the fraction with \( x \):
\[
\frac{x}{30} = \frac{2y}{5y - 180}.
\]
4. Cross-multiply to solve for \( x \):
\[
x = 30 \cdot \frac{2y}{5y - 180}.
\]
5. Simplify:
\[
x = \frac{60y}{5y - 180}.
\]
Now, \( x \) is the subject and can be expressed as:
\[
x = \frac{60y}{5y - 180}.
\]
\[
\frac{30}{x} + \frac{90}{y} = \frac{5}{2},
\]
follow these steps:
1. Isolate the term with \( x \):
\[
\frac{30}{x} = \frac{5}{2} - \frac{90}{y}.
\]
2. Find a common denominator for the right side:
\[
\frac{5}{2} = \frac{5y}{2y},
\]
so the equation becomes:
\[
\frac{30}{x} = \frac{5y - 180}{2y}.
\]
3. Take the reciprocal to eliminate the fraction with \( x \):
\[
\frac{x}{30} = \frac{2y}{5y - 180}.
\]
4. Cross-multiply to solve for \( x \):
\[
x = 30 \cdot \frac{2y}{5y - 180}.
\]
5. Simplify:
\[
x = \frac{60y}{5y - 180}.
\]
Now, \( x \) is the subject and can be expressed as:
\[
x = \frac{60y}{5y - 180}.
\]
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