Make x thesubject of formila in 30/x +90/y =5/2

1 answer

To make \( x \) the subject of the formula given by

\[ \frac{30}{x} + \frac{90}{y} = \frac{5}{2}, \]

follow these steps:

  1. Isolate the term with \( x \):

    \[ \frac{30}{x} = \frac{5}{2} - \frac{90}{y}. \]

  2. Find a common denominator for the right side:

    \[ \frac{5}{2} = \frac{5y}{2y}, \] so the equation becomes:

    \[ \frac{30}{x} = \frac{5y - 180}{2y}. \]

  3. Take the reciprocal to eliminate the fraction with \( x \):

    \[ \frac{x}{30} = \frac{2y}{5y - 180}. \]

  4. Cross-multiply to solve for \( x \):

    \[ x = 30 \cdot \frac{2y}{5y - 180}. \]

  5. Simplify:

    \[ x = \frac{60y}{5y - 180}. \]

Now, \( x \) is the subject and can be expressed as:

\[ x = \frac{60y}{5y - 180}. \]