1.2 mol of CH3OH(g) are injected into a 2.0 L container and the following equilibrium becomes established.

2H2(g) + CO(g) <=====> CH3OH(g) + 92 kJ
If at equilibrium 1.0 mol of CH3OH is still in the container the Ke must be which of the following?
a. 25 d. 12.5
b. 125 e. 0.032
c. 0.0080

Doing practice problems. Thanks!

4 answers

Write the equation.
Set up an ICE Chart.
Substitute in Keq expression and solve for Keq.
25
utv
It's 125