Asked by Jess

1.2 mol of CH3OH(g) are injected into a 2.0 L container and the following equilibrium becomes established.

2H2(g) + CO(g) <=====> CH3OH(g) + 92 kJ
If at equilibrium 1.0 mol of CH3OH is still in the container the Ke must be which of the following?
a. 25 d. 12.5
b. 125 e. 0.032
c. 0.0080


Doing practice problems. Thanks!
Answered by DrBob222
Write the equation.
Set up an ICE Chart.
Substitute in Keq expression and solve for Keq.
Answered by la
25
Answered by Anonymous
utv
Answered by Anonymous
It's 125
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