Question
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction. 594,297,448,453 How much total bond energy in kj/mol is intheproducts of the reaction?
Answers
GPT-4o mini
To calculate the total bond energy of the products in the reaction between hydrogen (H₂) and iodine (I₂) to produce hydroiodic acid (HI), we consider the bonds that are formed in the products.
1. **Balanced chemical reaction**: The reaction can be shown as:
\[
H_2(g) + I_2(g) \rightarrow 2 HI(g)
\]
2. **Bonds in the products**: In the products, there are 2 molecules of hydroiodic acid (HI). Each HI molecule has one H-I bond.
3. **Bond energy of H-I bond**: The bond energy is the energy required to break a bond between atoms. For HI, the typical bond energy is approximately \(298 \, \text{kJ/mol}\).
4. **Calculating the total bond energy in the products**: Since there are 2 moles of HI produced, the total bond energy for the 2 H-I bonds is:
\[
\text{Total bond energy} = 2 \times \text{Bond energy of H-I} = 2 \times 298 \, \text{kJ/mol} = 596 \, \text{kJ/mol}
\]
Therefore, the total bond energy in the products of the reaction (2 molecules of HI) is \(596 \, \text{kJ/mol}\).
1. **Balanced chemical reaction**: The reaction can be shown as:
\[
H_2(g) + I_2(g) \rightarrow 2 HI(g)
\]
2. **Bonds in the products**: In the products, there are 2 molecules of hydroiodic acid (HI). Each HI molecule has one H-I bond.
3. **Bond energy of H-I bond**: The bond energy is the energy required to break a bond between atoms. For HI, the typical bond energy is approximately \(298 \, \text{kJ/mol}\).
4. **Calculating the total bond energy in the products**: Since there are 2 moles of HI produced, the total bond energy for the 2 H-I bonds is:
\[
\text{Total bond energy} = 2 \times \text{Bond energy of H-I} = 2 \times 298 \, \text{kJ/mol} = 596 \, \text{kJ/mol}
\]
Therefore, the total bond energy in the products of the reaction (2 molecules of HI) is \(596 \, \text{kJ/mol}\).