Which linear equation has the same solution set as (9d)/4 + 3 - 2d = - 2(3 + d) (1 point) (3x)/5 - 10 = - 7 ○ 14 = 7/4 * x - 19/4 + 2x 35 - 15b = 95 4w - 2(7 - 3w) = w/3 - 6

To find which linear equation has the same solution set as \( \frac{9d}{4} + 3 - 2d = -2(3 + d) \), we can start by simplifying the original equation.

1. **Distributing on the right side:**
\[
\frac{9d}{4} + 3 - 2d = -6 - 2d
\]

2. **Adding \(2d\) to both sides to eliminate \(d\) on the right:**
\[
\frac{9d}{4} + 3 = -6
\]

3. **Subtracting \(3\) from both sides:**
\[
\frac{9d}{4} = -6 - 3
\]
\[
\frac{9d}{4} = -9
\]

4. **To remove the fraction, multiply both sides by \(4\):**
\[
9d = -36
\]

5. **Finally, divide by \(9\):**
\[
d = -4
\]

Now let's check the proposed equations:

1. **Equation 1: \( \frac{3x}{5} - 10 = -7 \)**
\[
\frac{3x}{5} = 3 \implies 3x = 15 \implies x = 5
\]
(Not equivalent)

2. **Equation 2: \( 14 = \frac{7}{4} x - \frac{19}{4} + 2x \)**
- Combine terms:
\[
14 = \frac{7}{4} x + \frac{8}{4} x - \frac{19}{4}
\]
\[
14 + \frac{19}{4} = \frac{15}{4} x
\]
Convert \(14\) to fraction:
\[
\frac{56}{4} + \frac{19}{4} = \frac{15}{4} x \implies \frac{75}{4} = \frac{15}{4} x \implies x = 5
\]
(Not equivalent)

3. **Equation 3: \( 35 - 15b = 95 \)**
\[
-15b = 95 - 35 \implies -15b = 60 \implies b = -4
\]
(Equivalent)

4. **Equation 4: \( 4w - 2(7 - 3w) = \frac{w}{3} - 6 \)**
\[
4w - 14 + 6w = \frac{w}{3} - 6
\]
\[
10w - 8 = \frac{w}{3} - 6
\]
Multiply the whole equation by 3:
\[
30w - 24 = w - 18
\]
\[
29w = 6 \implies w = \frac{6}{29}
\]
(Not equivalent)

The equation that has the same solution set as \(d = -4\) is \(35 - 15b = 95\).