A rectangular park has an area of 1.36 × 108 ft?

To find the width of the rectangular park, we can use the formula:

\[
\text{Width} = \frac{\text{Area}}{\text{Length}}
\]

Given:
- Area = \(1.36 \times 10^8 \, \text{ft}^2\)
- Length = \(1.6 \times 10^x \, \text{ft}\)

First, we need to clarify the value of \(x\). If we assume \(x = 1\) from the way you've written the length, then:

Length = \(1.6 \times 10^1 \, \text{ft} = 16 \, \text{ft}\)

Now we can calculate the width:

\[
\text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^1}
\]

Now divide the coefficients and subtract the exponents:

\[
\text{Width} = \frac{1.36}{1.6} \times 10^{8-1}
\]
\[
\text{Width} = 0.85 \times 10^{7}
\]

Now converting \(0.85 \times 10^7\) to scientific notation gives:

\[
8.5 \times 10^6 \, \text{ft}
\]

However, if you intended for the value of \(x\) to be different, then please let me know! Assuming that \(x\) was not \(1\) leads to corresponding changes in value. Assuming \(x = 2\) or others would yield:

\[
\text{Length} = 1.6 \times 10^2 \, \text{ft} = 160 \, \text{ft}
\]
In which case calculating becomes:

\[
\text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^2}
\]
\[
= 0.85 \times 10^{8-2}
\]
\[
= 0.85 \times 10^6 = 8.5 \times 10^5 \, \text{ft}
\]

Thus, if we assume \(x = 2\), the width of the park is:

**8.5 × 10^5 ft.**

So the correct answer is:

**8.5 × 10^5 ft.**