To find the width of the rectangular park, we can use the formula:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
Given:
- Area = \(1.36 \times 10^8 , \text{ft}^2\)
- Length = \(1.6 \times 10^x , \text{ft}\)
First, we need to clarify the value of \(x\). If we assume \(x = 1\) from the way you've written the length, then:
Length = \(1.6 \times 10^1 , \text{ft} = 16 , \text{ft}\)
Now we can calculate the width:
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^1} \]
Now divide the coefficients and subtract the exponents:
\[ \text{Width} = \frac{1.36}{1.6} \times 10^{8-1} \] \[ \text{Width} = 0.85 \times 10^{7} \]
Now converting \(0.85 \times 10^7\) to scientific notation gives:
\[ 8.5 \times 10^6 , \text{ft} \]
However, if you intended for the value of \(x\) to be different, then please let me know! Assuming that \(x\) was not \(1\) leads to corresponding changes in value. Assuming \(x = 2\) or others would yield:
\[ \text{Length} = 1.6 \times 10^2 , \text{ft} = 160 , \text{ft} \] In which case calculating becomes:
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^2} \] \[ = 0.85 \times 10^{8-2} \] \[ = 0.85 \times 10^6 = 8.5 \times 10^5 , \text{ft} \]
Thus, if we assume \(x = 2\), the width of the park is:
8.5 × 10^5 ft.
So the correct answer is:
8.5 × 10^5 ft.