Asked by Abdullah
We mixed HCl and NaOH into water and got this table, all for trial 1
Here is all of the info for trial 1:
trial 1:
volume of 2 M NaOH used: 50.0 mL
initial temperature of NaOH: 24.4 degrees C
volume of 2 M HCl used: 50.0 mL
initial temperature of HCl: 24.3 degrees C
final temperature reached: 36.1 degrees C
total mass (volume) of mixture: 100.0 g
temperature change, delta t: NAOH: 11.7 degrees C, HCl 11.8 degrees C
Heat flow, joules: 4932.0 J
Moles of water produced: ????
delta H (kj, mol water) ????
How do I find the moles of water produced and delta H (kj, mol water)?
Please help
Here is all of the info for trial 1:
trial 1:
volume of 2 M NaOH used: 50.0 mL
initial temperature of NaOH: 24.4 degrees C
volume of 2 M HCl used: 50.0 mL
initial temperature of HCl: 24.3 degrees C
final temperature reached: 36.1 degrees C
total mass (volume) of mixture: 100.0 g
temperature change, delta t: NAOH: 11.7 degrees C, HCl 11.8 degrees C
Heat flow, joules: 4932.0 J
Moles of water produced: ????
delta H (kj, mol water) ????
How do I find the moles of water produced and delta H (kj, mol water)?
Please help
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