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Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 de...Asked by epic
Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means
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Answers
Answered by
epic
make it into 3 sentences
Answered by
GPT-4o mini
To find the change in temperature from 9 a.m. to noon, we can set up the following equation:
\[
\text{Change in temperature} = \text{Temperature at noon} - \text{Temperature at 9 a.m.}
\]
Substituting the temperatures into the equation:
\[
\text{Change in temperature} = (-1.6) - (-5.8)
\]
Now, when we subtract a negative number, it is the same as adding its positive counterpart:
\[
\text{Change in temperature} = -1.6 + 5.8
\]
Next, we perform the addition:
\[
-1.6 + 5.8 = 4.2
\]
Thus, the change in temperature is:
\[
\text{Change in temperature} = 4.2 \text{ degrees Celsius}
\]
**Explanation:**
The result of 4.2 degrees Celsius indicates that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon. Initially, the temperature was -5.8 degrees Celsius, which is quite cold. By noon, the temperature had risen to -1.6 degrees Celsius. This means the air became warmer over the three-hour period.
\[
\text{Change in temperature} = \text{Temperature at noon} - \text{Temperature at 9 a.m.}
\]
Substituting the temperatures into the equation:
\[
\text{Change in temperature} = (-1.6) - (-5.8)
\]
Now, when we subtract a negative number, it is the same as adding its positive counterpart:
\[
\text{Change in temperature} = -1.6 + 5.8
\]
Next, we perform the addition:
\[
-1.6 + 5.8 = 4.2
\]
Thus, the change in temperature is:
\[
\text{Change in temperature} = 4.2 \text{ degrees Celsius}
\]
**Explanation:**
The result of 4.2 degrees Celsius indicates that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon. Initially, the temperature was -5.8 degrees Celsius, which is quite cold. By noon, the temperature had risen to -1.6 degrees Celsius. This means the air became warmer over the three-hour period.
Answered by
GPT-4o mini
The change in temperature from 9 a.m. to noon is calculated by subtracting the temperature at 9 a.m. (-5.8 degrees Celsius) from the temperature at noon (-1.6 degrees Celsius), resulting in a change of 4.2 degrees Celsius. This indicates that the temperature increased by 4.2 degrees Celsius during this time period. Therefore, the air became warmer, rising from a very cold -5.8 degrees Celsius to a less cold -1.6 degrees Celsius.
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