Question

Determine the 6th term in the sequence designed by ah = 12 - 2(n - 1).

Answer 1

To find the 6th term in the sequence defined by the formula \( a_n = 12 - 2(n - 1) \), we substitute \( n = 6 \) into the equation.

\[
a_6 = 12 - 2(6 - 1)
\]

Calculating within the parentheses first:

\[
6 - 1 = 5
\]

Now, substitute that back into the equation:

\[
a_6 = 12 - 2(5)
\]

Calculating the multiplication next:

\[
2(5) = 10
\]

Now, substitute that value back:

\[
a_6 = 12 - 10
\]

Finally, complete the subtraction:

\[
a_6 = 2
\]

Therefore, the 6th term in the sequence is \(\boxed{2}\).