Autograph with X being from 0 to 6 and why being 0 to 6 why is distance in feet x is times seconds point a is from 0 x to y 6 point B is 0x2 why six point C is 0x2y3 which means objects is moving at a rate of 2 ft per second a object B b c c a d all of the objects

1 answer

It seems like you're attempting to describe a scenario involving three points (A, B, and C) defined by coordinates related to an object's movement over time. However, the description is a bit unclear. Let me clarify what I think you are asking about and provide an explanation based on that.

Points Defined:

  • Point A: \((0, 6)\)
  • Point B: \((0, 2)\)
  • Point C: \((0, 3)\)

The coordinates appear to have the structure \((x, y)\) where 'x' might represent time (in seconds from 0 to 6), and 'y' represents distance (in feet).

Movement:

You mentioned an object moving at a rate of 2 feet per second. Let's break this down:

  • If the object is at Point A initially (at 6 feet), and it moves at a constant speed of 2 ft/s, you can find the distance traveled over the time interval defined by 'x' from 0 to 6 seconds.

Distance Calculations:

  1. From Point A to Point B:

    • Point A (at y=6) to Point B (at y=2):
    • Distance = Initial distance - Distance covered = 6 ft - (2 ft/s × time).
    • To find the time taken to reach Point B, we set the equation: \[ 6 - 2t = 2 \] which can be rearranged to find: \[ 2t = 4 \quad \Rightarrow \quad t = 2 \text{ seconds.} \]
  2. From Point B to Point C:

    • Moving from Point B (y=2) to Point C (y=3):
    • Distance = 3 ft - 2 ft = 1 ft.
    • At the speed of 2 ft/s, time taken to travel this 1 ft would be: \[ t = \frac{1 \text{ ft}}{2 \text{ ft/s}} = 0.5 \text{ seconds.} \]
  3. Total Movement Time:

    • Time from A to B: 2 seconds
    • Time from B to C: 0.5 seconds
    • Total time from A to C: \(2 + 0.5 = 2.5\) seconds.

Conclusion:

Based on your description, it appears you are visualizing an object that starts at point A, moves to point B, and then to point C. The speed and movement can be calculated as shown above.

If you meant something else or needed specific calculations or interpretations, please clarify your request, and I would be happy to help further!