Question

Rewrite the equation 5/2x−8−1=9 as two equations joined by “and.”(1 point)
Responses

5/2x−8=9 and x≠−8
Start Fraction 5 over 2 x minus 8 End Fraction equals 9 and x does not equal negative 8

5/2x−8−1=9 and x≠8
Start Fraction 5 over 2 x minus 8 End Fraction minus 1 equals 9 and x does not equal 8

5/2x−8−1=9 and x≠4
Start Fraction 5 over 2 x minus 8 End Fraction minus 1 equals 9 and x does not equal 4

5/2x−8−1=9 and x≠−4

Answer 1

To rewrite the equation \( \frac{5}{2}x - 8 - 1 = 9 \), we first simplify it:

\[
\frac{5}{2}x - 9 = 9
\]

Now, we separate it into two equations:

1. \( \frac{5}{2}x - 9 = 9 \)
2. To maintain the conditions of the equation, we can note that the simplified term must satisfy the equality, so we'll leave it without any additional restrictions here, as there are no values that would inherently make this equation undefined.

So, the rewritten equation can be:

\[
\frac{5}{2}x - 9 = 9 \text{ and } x \text{ may take any real number.}
\]

However, reflecting on your provided responses to find a condition regarding \(x\), we consider that \(x\) must be a real number solution to the original equation setup. Thus:

Choosing from your responses, the one that makes logical sense with the conditions implied might be:
\[
\frac{5}{2}x - 8 - 1 = 9 \text{ and } x \neq -8
\]

This implies that the first part is consistent with the equation you provided, and the second part asserts a condition that makes sense if \(x\) were indeed adverse to a specific resolution (usually designed to eliminate undefined elements). However, if we effectively follow the first logical step of adjusting the original equation without real restrictions, your first response adequately captures the scope.

If there were a mistake in the given options involving adjustments or misunderstandings resulting from the simplification process, re-evaluating those equations could adjust those implications further.

For the response to be specific and precise:
\(\frac{5}{2}x - 9 = 9\) and \(x \neq 8\) will indeed match through the residue of observations, whereas focusing on \( \frac{5}{2}x - 9 = 9 \) captures the essence clearly.

Final actionable recall might be refined to assess adding conditions specifically without overriding non-negative or mutual values.