Redraw thius as an acytual equation, with symbols and words.

The equation for the temperature drop per hour is:
\[
\text{Rate} = \frac{\text{Initial temp} - \text{Final temp}}{\text{Time interval}} = \frac{82 - 62}{5} = 4°F \text{ per hour}
\]

1 answer

Certainly! Here’s the equation represented using symbols and words:

Let:

  • \( R \) = Rate of temperature drop (°F per hour)
  • \( T_i \) = Initial temperature (°F)
  • \( T_f \) = Final temperature (°F)
  • \( \Delta t \) = Time interval (hours)

The formula for the rate of temperature drop can be expressed as:

\[ R = \frac{T_i - T_f}{\Delta t} \]

Inserting the given values:

\[ R = \frac{82 - 62}{5} \]

Calculating the result:

\[ R = \frac{20}{5} = 4 , \text{°F per hour} \]

So, the equation for the temperature drop per hour is:

\[ R = 4 , \text{°F per hour} \]