Asked by marina
from the equation : c3h8+5O2=3CO2+4H20
HOW MANY GRAMS OF H2O CAN BE PRODUCED FROM THE REACTION OF 8.5X10^22 MOLECULES PROPANE GAS, C3H8
HOW MANY GRAMS OF H2O CAN BE PRODUCED FROM THE REACTION OF 8.5X10^22 MOLECULES PROPANE GAS, C3H8
Answers
Answered by
DrBob222
Rewrite the equation in standard form.
C3H8 + 5O2 ==> 3CO2 + 4H2O.
2. Convert 8.5 x 10^22 molecules propane into moles. Remember 1 mole contains 6.02 x 10^23 molecules.
3. Using the coefficients in the balanced equation, convert moles propane to moles H2O.
4. Convert mols H2O to grams. g = moles x molar mass.
C3H8 + 5O2 ==> 3CO2 + 4H2O.
2. Convert 8.5 x 10^22 molecules propane into moles. Remember 1 mole contains 6.02 x 10^23 molecules.
3. Using the coefficients in the balanced equation, convert moles propane to moles H2O.
4. Convert mols H2O to grams. g = moles x molar mass.
Answered by
CHAN
14.6 g H2O
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