A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×105

gallons of water. How many tetras can it house? Write the answer in scientific notation.(1 point)
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1 answer

To find out how many neon tetras can be housed in the aquarium, we can use the following calculation:

  1. The total capacity of the aquarium is \( 1 \times 10^5 \) gallons.
  2. Each neon tetra requires 1.25 gallons of water.

To find the number of tetras that can be accommodated, we divide the total gallons by the gallons needed per tetra:

\[ \text{Number of tetras} = \frac{1 \times 10^5 \text{ gallons}}{1.25 \text{ gallons/tetra}} \]

Now, let's perform the division:

\[ \frac{1 \times 10^5}{1.25} = 0.8 \times 10^5 \]

To express \( 0.8 \times 10^5 \) in scientific notation, we can adjust it:

\[ 0.8 \times 10^5 = 8.0 \times 10^4 \]

Thus, the number of neon tetras the aquarium can house is

\[ \boxed{8.0 \times 10^4} \]