To solve the compound inequality \(-2 ≤ 2x + 13 - 4 < 1\), we can break it into two separate inequalities:
- \(-2 ≤ 2x + 13 - 4\)
- \(2x + 13 - 4 < 1\)
We'll simplify each of these inequalities step by step.
Step 1: Solve the first inequality
\(-2 ≤ 2x + 13 - 4\) simplifies to:
\[ -2 ≤ 2x + 9 \]
Subtract 9 from both sides:
\[ -11 ≤ 2x \]
Divide by 2:
\[ -\frac{11}{2} ≤ x \]
This can also be written as:
\[ x ≥ -\frac{11}{2} \]
Step 2: Solve the second inequality
The second inequality \(2x + 13 - 4 < 1\) simplifies to:
\[ 2x + 9 < 1 \]
Subtract 9 from both sides:
\[ 2x < -8 \]
Divide by 2:
\[ x < -4 \]
Step 3: Combine the results
Now we combine the results from both inequalities:
\[ -\frac{11}{2} ≤ x < -4 \]
Step 4: Convert to decimal
\(-\frac{11}{2} = -5.5\), so the final inequality is:
\[ -5.5 ≤ x < -4 \]
Step 5: Write the solution in set notation
In set notation, this can be expressed as:
\[ {x : -5.5 ≤ x < -4} \]
Finding the correct answer among the options:
None of your provided options exactly match \(-5.5 ≤ x < -4\). The given options do not seem to reflect the solution we derived. Therefore, it may be necessary to double-check the problem or the options provided.
However, following the steps shown above, the solution to the inequality is definitely:
\[ {x : -\frac{11}{2} ≤ x < -4} \]