To find the width of the park, you can use the formula for the area of a rectangle, which is:
\[ \text{Area} = \text{Length} \times \text{Width} \]
From this, we can solve for the width:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
Given:
- Area = \( 1.36 \times 10^8 , \text{ft}^2 \)
- Length = \( 1.6 \times 10^4 , \text{ft} \)
Now, substitute the values into the formula for width:
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^4} \]
To perform the division, we can divide the coefficients and subtract the exponents:
\[ \text{Width} = \frac{1.36}{1.6} \times 10^{8 - 4} \]
Calculating the coefficient:
\[ \frac{1.36}{1.6} = 0.85 \]
Now substituting back into the equation:
\[ \text{Width} = 0.85 \times 10^4 \]
To convert \( 0.85 \) into scientific notation:
\[ 0.85 = 8.5 \times 10^{-1} \]
So:
\[ \text{Width} = 8.5 \times 10^{-1} \times 10^4 = 8.5 \times 10^{3} \]
Thus, the width of the park is:
\[ \text{Width} = 8.5 \times 10^3 , \text{ft} \]
The correct response is 8.5×103 ft (8.5 times 10 cubed ft).
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