review the graphs of a system of two linear equations in two variables: x-5y=7 and 3x-2y=-4

Answer 1

To review the graphs of the system of two linear equations given by:

1. \( x - 5y = 7 \)
2. \( 3x - 2y = -4 \)

We'll start by rewriting each equation in slope-intercept form (y = mx + b) for easier graphing.

First Equation: \( x - 5y = 7 \)

Rearranging gives:

\[ -5y = -x + 7 \]

Dividing by -5 results in:

\[ y = \frac{1}{5}x - \frac{7}{5} \]

From this, we can see the slope \( m_1 = \frac{1}{5} \) and the y-intercept \( b_1 = -\frac{7}{5} \).

Second Equation: \( 3x - 2y = -4 \)

Rearranging gives:

\[ -2y = -3x - 4 \]

Dividing by -2 results in:

\[ y = \frac{3}{2}x + 2 \]

Here, the slope \( m_2 = \frac{3}{2} \) and the y-intercept \( b_2 = 2 \).

Graphing the Equations

1. For the first equation \( y = \frac{1}{5}x - \frac{7}{5} \):

   • The y-intercept is \( -\frac{7}{5} \) (approximately -1.4). This is the point (0, -1.4).
   • Using the slope \( \frac{1}{5} \), from (0, -1.4), if we go right 5 units (to x = 5), we go up 1 unit (to y = -1.4 + 1 = -0.4). This gives the point (5, -0.4).

2. For the second equation \( y = \frac{3}{2}x + 2 \):

   • The y-intercept is \( 2 \) (the point (0, 2)).
   • Using the slope \( \frac{3}{2} \), from (0, 2), if we go right 2 units (to x = 2), we go up 3 units (to y = 2 + 3 = 5). This gives the point (2, 5).

Finding the Intersection

To find the intersection (the solution to the system), we can solve the equations simultaneously:

From the first equation: \[ x = 5y + 7 \]

Substituting into the second equation: \[ 3(5y + 7) - 2y = -4 \] \[ 15y + 21 - 2y = -4 \] \[ 13y + 21 = -4 \] \[ 13y = -25 \] \[ y = -\frac{25}{13} \]

Substituting back to find \(x\): \[ x = 5\left(-\frac{25}{13}\right) + 7 = -\frac{125}{13} + \frac{91}{13} = -\frac{34}{13} \]

Conclusion

The solution to the system of equations is \( \left(-\frac{34}{13}, -\frac{25}{13}\right) \).

In summary:

• The first equation's graph is a line with a gentle slope that starts below the x-axis.
• The second equation's graph is a steeper line that rises more quickly and crosses the y-axis at 2.
• The two lines intersect at \( \left(-\frac{34}{13}, -\frac{25}{13}\right) \), which represents the solution to the system.