If more sugar were added to the solution on the left side of the tube, what would happen to the water level on the right side of the tube?

Question

A U-shaped tube with two arms separated by a membrane at the base of the U. Both arms contain solution with similar concentration of sugar. The fluid level on the left side of the tube is lower than the fluid level on the right side.

The water level would stay the same.
The water level would rise.
The water level would go down.
Request Answer
Part D
If the pores in the selectively permeable membrane became larger, but still not large enough to let the sugar pass through, what would happen during osmosis in the U-shaped tube compared to what is shown in the figure?

Two U-shaped tubes representing two states during osmosis. Both tubes have a membrane at their bases. The tube on the left has equal fluid levels in arms. Arm A contains solution with lower concentration of solute, arm B contains solution with higher concentration of solute. Water pass from arm A to arm B. After osmosis the tube on the right contains solutions with similar concentration of solute in both arms. The fluid level on arm A is lower than the fluid level on arm B.

The final water levels would be the same as shown in the figure, but the solutions would reach near equal concentrations faster.
More water could pass to the right side of the tube so the water level would rise even higher.
There would be less free water on the left side of the tube, so the water level on the right would not get as high.
Some water would be pushed back to the left side through the larger pores, so the water level on the right would not get as high.

Answer 1

Part C Answer: If more sugar were added to the solution on the left side of the tube, the water level on the right side of the tube would rise.

Here's why: In osmosis, water moves from an area of lower solute concentration to an area of higher solute concentration. By adding more sugar to the left side, you are increasing the solute concentration on that side, which will draw more water towards the left side initially. However, since the membrane is selectively permeable to water and not to the sugar, water will move from the right side (where the concentration of sugar is lower) to the left. This will cause the water level on the right side to rise.

---

Part D Answer: If the pores in the selectively permeable membrane became larger, but still not large enough to let the sugar pass through, the final water levels would be the same as shown in the figure, but the solutions would reach near equal concentrations faster.

In this scenario, because the pores are larger, water can move more freely between the two sides of the tube. This increased permeability would allow water to equilibrate more quickly between the two sides, though the solute (sugar) would still not be able to pass through the membrane. As a result, while the final concentration of solute may remain unchanged, the time taken to reach equilibrium would be reduced.