Solve for x to determine if the equation has one, none, or infinite solutions.

4x=3(x+5)-15
The equation has one solution: x=0
The equation has no solution.
The equation has one solution:x=-10
The equation has infinite solutions.

1 answer

To solve the equation \( 4x = 3(x + 5) - 15 \), we start by simplifying both sides.

First, simplify the right side:

\[ 3(x + 5) = 3x + 15 \] Now substitute back into the equation:

\[ 4x = 3x + 15 - 15 \]

This simplifies to:

\[ 4x = 3x \]

Next, subtract \( 3x \) from both sides:

\[ 4x - 3x = 0 \] \[ x = 0 \]

Now let's analyze the result. We found that \( x = 0 \) is a solution.

To also determine the type of solution, consider the steps we took:

If the equation simplifies to a true statement with no variable remaining (like \( 0 = 0 \)), then there would be infinite solutions. If it simplifies to a contradiction (like \( 0 = 5 \)), there would be no solution. In our case, we ended up with one variable solution.

Thus, the final conclusion is:

The equation has one solution: \( x = 0 \).