Finish the equation so that the equation has infinite amount of solutions.

Let's solve the problems one by one.

### 1. Finish the equation so that it has an infinite amount of solutions.
To have infinite solutions, both sides of the equation must be identically equal, meaning they can be simplified to the same expression.

Starting from:
\[ 6(9x + 4) - 5 = \text{?} \]

First, simplify the left side:
\[
6(9x + 4) - 5 = 54x + 24 - 5 = 54x + 19
\]

So we need to fill in the right side with the same expression:
\[
6(9x + 4) - 5 = 54x + 19
\]

**Final Answer:**
\[ 6(9x + 4) - 5 = 54x + 19 \]

### 2. Finish the equation so that it has zero solutions.
To create an equation with zero solutions, the expressions on both sides must not be equal, even after simplification.

Starting from:
\[ 2(7x + 4) - 4 = \text{?} \]

First, simplify the left side:
\[
2(7x + 4) - 4 = 14x + 8 - 4 = 14x + 4
\]

Now we want to equate this to something that would be different. For example, we could set it equal to an expression that cannot equal \(14x + 4\). A simple way is to add constants such that the result cannot be simplified to the left side.

Let’s set it to a different constant:
- The relationship can be made as follows:
\[
2(7x + 4) - 4 = 14x + 5
\]

This creates an inconsistency, as \(14x + 4\) can never equal \(14x + 5\).

**Final Answer:**
\[ 2(7x + 4) - 4 = 14x + 5 \]

### 3. Find the value of x that makes the following have exactly 1 solution.
To find the value of \(x\) that yields exactly 1 solution, the equations must be linear and have a unique intersection.

From the equation:
\[ 2(2x + 8) = 2x + 2 \]

Simplify the left side:
\[
4x + 16 = 2x + 2
\]

Now, isolate \(x\):
\[
4x - 2x = 2 - 16 \\
2x = -14 \\
x = -7
\]

Therefore, the value of \(x\) that results in exactly one solution is:

**Final Answer:**
\[ x = -7 \]