A nutritionist wants a patient to intake at most

Question

1
,
800
calories a day. The patient has already eaten
1
,
450
calories today. The patient plans to eat
5
snacks that each have an equal number of calories for the remainder of the day’s calories.

Which inequality represents the maximum number of calories the patient can consume for each snack,
c
,
without exceeding the nutritionist’s daily caloric intake limit?

Responses

1
,
450
+
5
c
≤
1
,
800
1 , 450 + 5 c ≤ 1 , 800

1
,
450
+
5
c
≥
1
,
800
1 , 450 + 5 c ≥ 1 , 800

1
,
800
+
5
c
≤
1
,
450
1 , 800 + 5 c ≤ 1 , 450

1
,
800
+
5
c
≥
1
,
450

Answer 1

To determine the correct inequality, we need to express the total caloric intake as the sum of the calories already eaten and the calories from the snacks the patient plans to eat.

The patient has already consumed 1,450 calories and is planning to eat 5 snacks. If we let \( c \) represent the number of calories per snack, then the total caloric intake from the snacks is \( 5c \).

The patient should not exceed a total of 1,800 calories combined from what has already been eaten and the snacks. This can be expressed with the following inequality:

\[ 1,450 + 5c \leq 1,800 \]

Thus, the correct response is:

1,450 + 5c ≤ 1,800