3(6x+5)=2x+______x+_________

To solve the equation \(3(6x + 5) = 2x + \_\_\_\_ x + \_\_\_\_\), we first simplify the left side:

1. Distribute the 3:
\[
3(6x + 5) = 3 \cdot 6x + 3 \cdot 5 = 18x + 15.
\]

So, we have:
\[
18x + 15 = 2x + \_\_\_\_ x + \_\_\_\_.
\]

Next, let's rearrange the terms on the right side. We want to represent \(18x + 15\) in the form \(2x + Ax + B\), where \(A\) and \(B\) are the missing values we need to determine.

2. Combine like terms on the right side:
\[
2x + Ax + B = (2 + A)x + B.
\]

To make both sides of the equation equal, we compare coefficients:

- For terms involving \(x\):
\[
18 = 2 + A.
\]

This gives:
\[
A = 18 - 2 = 16.
\]

- For the constant terms:
\[
15 = B.
\]

Thus, we find:
- \(A = 16\)
- \(B = 15\)

Now we can fill in the blanks:
\[
3(6x + 5) = 2x + 16x + 15.
\]

The completed equation is:
\[
3(6x + 5) = 2x + 16x + 15.
\]