Question

Each row of the table shows a different speed-distance-time relationship.

A 3-column table with 2 rows. Column 1 is labeled Speed (meters per hour) with entries 35, 27. Column 2 is labeled Distance (meters) with entries A, 81. Column 3 is labeled Time (hours) with entries 4, B.

Use the drop-down menus to correctly complete the table.

A =
B =

Answer 1

To find the values of A and B in the table, we can use the relationship between speed, distance, and time, which is given by the formula:

\[
\text{Distance} = \text{Speed} \times \text{Time}
\]

We'll work through each row of the table.

### For Row 1:
- **Speed = 35 meters/hour**
- **Time = 4 hours**
- We need to find Distance (A).

Using the formula:
\[
\text{Distance} = 35 \times 4 = 140 \text{ meters}
\]
So, A = 140.

### For Row 2:
- **Distance = 81 meters**
- **Speed = 27 meters/hour**
- We need to find Time (B).

Again, using the formula rearranged:
\[
\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{81}{27} = 3 \text{ hours}
\]
So, B = 3.

### Final Answers:
A = 140
B = 3