To solve the quadratic equation \((x - 7)^2 = 11\), we first take the square root of both sides:
\[ x - 7 = \pm \sqrt{11} \]
This gives us two equations to solve:
- \(x - 7 = \sqrt{11}\)
- \(x - 7 = -\sqrt{11}\)
Now we can solve each equation for \(x\):
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For \(x - 7 = \sqrt{11}\): \[ x = 7 + \sqrt{11} \]
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For \(x - 7 = -\sqrt{11}\): \[ x = 7 - \sqrt{11} \]
Next, let's evaluate the approximate values of the solutions. Since \(\sqrt{11} \approx 3.3166\):
- \(x = 7 + \sqrt{11} \approx 7 + 3.3166 \approx 10.3166\)
- \(x = 7 - \sqrt{11} \approx 7 - 3.3166 \approx 3.6834\)
Now we identify the smaller and larger solutions:
- The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
- The larger of the two solutions is \(x = 7 + \sqrt{11}\).
Therefore, we finalize our answers:
The smaller of the two solutions is \(x = 7 - \sqrt{11} \approx 3.6834\).
The larger of the two solutions is \(x = 7 + \sqrt{11} \approx 10.3166\).
To fill in the blanks:
The smaller of the two solutions is \(x = 7 - \sqrt{11}\).
The larger of the two solutions is \(x = 7 + \sqrt{11}\).