Question
What is the common ratio in the following geometric sequence?
2, 1/2, 1/8, 1/32,...
(1 point)
Responses
-1.5
-1.5
4
4
1/2
1 half
1/4
2, 1/2, 1/8, 1/32,...
(1 point)
Responses
-1.5
-1.5
4
4
1/2
1 half
1/4
Answers
Answered by
GPT-4o mini
To find the common ratio of a geometric sequence, you divide any term by the term preceding it.
For the sequence \(2, \frac{1}{2}, \frac{1}{8}, \frac{1}{32},...\):
1. Divide the second term by the first term:
\[
\frac{1/2}{2} = \frac{1}{2} \div 2 = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]
2. Divide the third term by the second term:
\[
\frac{1/8}{1/2} = \frac{1}{8} \div \frac{1}{2} = \frac{1}{8} \times \frac{2}{1} = \frac{1}{4}
\]
3. Divide the fourth term by the third term:
\[
\frac{1/32}{1/8} = \frac{1}{32} \div \frac{1}{8} = \frac{1}{32} \times \frac{8}{1} = \frac{1}{4}
\]
In each case, the common ratio is \(\frac{1}{4}\).
Thus, the common ratio of the sequence is:
**1/4**
For the sequence \(2, \frac{1}{2}, \frac{1}{8}, \frac{1}{32},...\):
1. Divide the second term by the first term:
\[
\frac{1/2}{2} = \frac{1}{2} \div 2 = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]
2. Divide the third term by the second term:
\[
\frac{1/8}{1/2} = \frac{1}{8} \div \frac{1}{2} = \frac{1}{8} \times \frac{2}{1} = \frac{1}{4}
\]
3. Divide the fourth term by the third term:
\[
\frac{1/32}{1/8} = \frac{1}{32} \div \frac{1}{8} = \frac{1}{32} \times \frac{8}{1} = \frac{1}{4}
\]
In each case, the common ratio is \(\frac{1}{4}\).
Thus, the common ratio of the sequence is:
**1/4**