have? You do not need to solve for x.(1 point)
The equation would have
solution(s).
3 answers
The equation \( x^2 = -9 \) would have no real solutions because the square of a real number cannot be negative. However, there are complex solutions.
In the complex number system, this equation can be rewritten as:
\[ x^2 = -9 \implies x = \pm \sqrt{-9} = \pm 3i \]
Thus, there are 2 complex solutions.
So the equation would have 2 solution(s).
I apologize for any confusion. Let's clarify:
The equation \( x^2 = -9 \) indeed has two complex solutions, which are \( x = 3i \) and \( x = -3i \). However, if we are discussing solutions in the context of real numbers, there are no real solutions since \( x^2 \) cannot equal a negative number.
If we consider only the real number solutions, the answer would be 0 solutions.
If your question is strictly about complex numbers, then it would have 2 complex solutions. Please confirm the context you need, and I'll be glad to assist further!
