Question

determine the zeros in y = -5x^2 + 16x

Answer 1

To find the zeros of the equation \( y = -5x^2 + 16x \), we set \( y \) to zero and solve for \( x \):

\[
-5x^2 + 16x = 0
\]

We can factor this equation:

\[
x(-5x + 16) = 0
\]

Setting each factor equal to zero gives us:

1. \( x = 0 \)
2. \( -5x + 16 = 0 \)

Now, solve the second equation:

\[
-5x + 16 = 0 \\
-5x = -16 \\
x = \frac{16}{5}
\]

Thus, the zeros of the equation \( y = -5x^2 + 16x \) are:

\[
x = 0 \quad \text{and} \quad x = \frac{16}{5}
\]

In conclusion, the zeros are \( x = 0 \) and \( x = \frac{16}{5} \) (or \( 3.2 \)).