Question
Multiply in Scientific Notation Practice
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Question
The weight of an ant averages about 3×10−6
kg. There are about 1×1016
ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation.(1 point)
kg
Remaining Attempts : 3
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Answers
GPT-4o mini
To find the total weight of all the ants in the world, we need to multiply the average weight of one ant by the total number of ants.
Given:
- Average weight of one ant = \(3 \times 10^{-6}\) kg
- Number of ants = \(1 \times 10^{16}\)
The multiplication in scientific notation follows the formula:
\[
(a \times 10^m) \times (b \times 10^n) = (a \times b) \times 10^{(m+n)}
\]
So we can compute the total weight as follows:
\[
(3 \times 10^{-6}) \times (1 \times 10^{16}) = 3 \times 1 \times 10^{-6 + 16}
\]
Calculating the values:
\[
3 \times 1 = 3
\]
\[
-6 + 16 = 10
\]
Thus, the total weight of all the ants is:
\[
3 \times 10^{10} \text{ kg}
\]
So the approximate weight in kilograms of all the ants in the world is:
\[
\boxed{3 \times 10^{10}} \text{ kg}
\]
Given:
- Average weight of one ant = \(3 \times 10^{-6}\) kg
- Number of ants = \(1 \times 10^{16}\)
The multiplication in scientific notation follows the formula:
\[
(a \times 10^m) \times (b \times 10^n) = (a \times b) \times 10^{(m+n)}
\]
So we can compute the total weight as follows:
\[
(3 \times 10^{-6}) \times (1 \times 10^{16}) = 3 \times 1 \times 10^{-6 + 16}
\]
Calculating the values:
\[
3 \times 1 = 3
\]
\[
-6 + 16 = 10
\]
Thus, the total weight of all the ants is:
\[
3 \times 10^{10} \text{ kg}
\]
So the approximate weight in kilograms of all the ants in the world is:
\[
\boxed{3 \times 10^{10}} \text{ kg}
\]