The average newborn weighs 7.5 pounds. About 4.1×10^6 babies are born in the United States every year. What is the approximate total weight in pounds of all the babies born in the U.S. in a year? Write the answer in scientific notation, expressed to the exact decimal place.(1 point)

Answer 1

To find the total weight of all the babies born in the U.S. in a year, we can multiply the average weight of a newborn by the number of babies born.

The average weight of a newborn is 7.5 pounds, and the number of babies born each year is approximately \( 4.1 \times 10^6 \).

The calculation is as follows:

\[ \text{Total Weight} = \text{Average Weight} \times \text{Number of Babies} = 7.5 , \text{pounds} \times 4.1 \times 10^6 \]

Calculating this gives:

\[ \text{Total Weight} = 7.5 \times 4.1 = 30.75 \]

Now, we incorporate the \( 10^6 \):

\[ \text{Total Weight} = 30.75 \times 10^6 \]

To express this value in proper scientific notation, we can rewrite \( 30.75 \) as \( 3.075 \times 10^1 \):

\[ \text{Total Weight} = 3.075 \times 10^1 \times 10^6 = 3.075 \times 10^{1+6} = 3.075 \times 10^7 \]

Thus, the approximate total weight in pounds of all the babies born in the U.S. in a year is:

\[ \boxed{3.075 \times 10^7} \]

Answer 2

In a given year, about 1.52×1010 pieces of first-class mail are delivered in the U.S. If each piece of mail carries a stamp costing $0.55, what is the total cost in dollars to deliver all the pieces? Write the answer in scientific notation, expressed to the exact decimal place.(1 point) $

Answer 3

To find the total cost of delivering all the pieces of mail, we can multiply the number of pieces of mail by the cost of a stamp for each piece.

Given:

• Number of pieces of mail: \( 1.52 \times 10^{10} \)
• Cost of each stamp: \( 0.55 \) dollars

Now, we can calculate the total cost:

\[ \text{Total Cost} = \text{Number of Pieces of Mail} \times \text{Cost of Each Stamp} = (1.52 \times 10^{10}) \times 0.55 \]

Calculating the multiplication:

\[ 1.52 \times 0.55 = 0.836 \]

Now, we incorporate the \( 10^{10} \):

\[ \text{Total Cost} = 0.836 \times 10^{10} \]

To express this value in proper scientific notation, we need to convert \( 0.836 \) to scientific notation:

\[ 0.836 = 8.36 \times 10^{-1} \]

Now we combine it with \( 10^{10} \):

\[ \text{Total Cost} = 8.36 \times 10^{-1} \times 10^{10} = 8.36 \times 10^{10-1} = 8.36 \times 10^{9} \]

Thus, the total cost in dollars to deliver all the pieces is:

\[ \boxed{8.36 \times 10^9} \]

Answer 4

What is 5.5×104 multiplied by 2.2×10−8 ? Write the answer in scientific notation.(1 point) Responses 1.21×10−3 1.21 times 10 negative cubed 1.21×10−4 1.21 times 10 superscript negative 4 baseline 12.1×10−4 12.1 times 10 superscript negative 4 baseline 1.21×10−5 1.21 times 10 superscript negative 5 baseline Skip to navigation page 14 of 14

Answer 5

To multiply the numbers \(5.5 \times 10^4\) and \(2.2 \times 10^{-8}\), we will follow the rules for multiplying numbers in scientific notation.

1. First, multiply the coefficients (the numbers before the powers of 10): \[ 5.5 \times 2.2 = 12.1 \]

2. Next, add the exponents of the powers of 10: \[ 10^4 \times 10^{-8} = 10^{4 + (-8)} = 10^{-4} \]

3. Now, combine these results: \[ 12.1 \times 10^{-4} \]

4. Finally, we need to express this in proper scientific notation. Since the coefficient \(12.1\) is greater than 10, we need to convert it: \[ 12.1 = 1.21 \times 10^1 \]

5. Therefore, we combine: \[ 12.1 \times 10^{-4} = 1.21 \times 10^1 \times 10^{-4} = 1.21 \times 10^{1 - 4} = 1.21 \times 10^{-3} \]

The final answer in scientific notation is: \[ \boxed{1.21 \times 10^{-3}} \]

Answer 6

When multiplying two numbers in scientific notation, what operations do you use on the coefficients and the exponents of the powers of 10?(1 point) Responses Add the coefficients and multiply the exponents of the powers of 10. Add the coefficients and multiply the exponents of the powers of 10. Multiply the coefficients and add the exponents of the powers of 10. Multiply the coefficients and add the exponents of the powers of 10. Multiply the coefficients and multiply the exponents of the powers of 10. Multiply the coefficients and multiply the exponents of the powers of 10. Add the coefficients and add the exponents of the powers of 10. Add the coefficients and add the exponents of the powers of 10. Skip to navigation page 14 of 14

Answer 7

When multiplying two numbers in scientific notation, the correct operations are:

• Multiply the coefficients (the numbers in front of the powers of 10).
• Add the exponents of the powers of 10.

So, the correct response is:

\[ \text{Multiply the coefficients and add the exponents of the powers of 10.} \]

Thus, the answer is:

\[ \boxed{\text{Multiply the coefficients and add the exponents of the powers of 10.}} \]

Answer 8

A tape dispenser holds 1.14×104 mm of tape that is 12.7 mm wide. Multiply the two numbers to find the total area in square millimeters of tape. Write the product in scientific notation.(1 point) Responses 1.4478×105 mm2 1.4478 times 10 superscript 5 baseline mm squared 1.4478×104 mm2 1.4478 times 10 superscript 4 baseline mm squared 14.478×104 mm2 14.478 times 10 superscript 4 baseline mm squared 14.478×105 mm2 14.478 times 10 superscript 5 baseline mm squared Skip to navigation page 14 of 14

Answer 9

To find the total area of the tape in square millimeters, we need to multiply the length of the tape by its width.

Given:

• Length of tape = \(1.14 \times 10^4\) mm
• Width of tape = \(12.7\) mm

Now, we can perform the calculation:

1. Multiply the coefficients: \[ 1.14 \times 12.7 = 14.478 \]

2. Add the exponents: \[ 10^4 \text{ (from the length)} \text{ and } 10^0 \text{ (since } 12.7 \text{ is } 10^0) \text{ gives us } 10^{4 + 0} = 10^4. \]

3. Combine these results: \[ \text{Area} = 14.478 \times 10^4 \text{ mm}^2. \]

Next, we need to express \(14.478 \times 10^4\) in proper scientific notation. Since \(14.478\) is greater than \(10\), we convert it to: \[ 14.478 = 1.4478 \times 10^1. \]

Now, combine this with \(10^4\): \[ 14.478 \times 10^4 = 1.4478 \times 10^1 \times 10^4 = 1.4478 \times 10^{1 + 4} = 1.4478 \times 10^5 \text{ mm}^2. \]

Therefore, the total area of the tape in square millimeters is: \[ \boxed{1.4478 \times 10^5 , \text{mm}^2}. \]