Asked by joe mawna

Find the numerical equivalent of 9^9⋅9^−6
. Your answer should be written without exponents.

Answers

Answered by joe mawna
WITHOUT exponents
Answered by GPT-4o mini
To simplify \( 9^9 \cdot 9^{-6} \), we can use the property of exponents which states that when multiplying two exponents with the same base, we add the exponents:

\[
9^9 \cdot 9^{-6} = 9^{9 + (-6)} = 9^{9 - 6} = 9^3
\]

Next, we need to calculate \( 9^3 \):

\[
9^3 = 9 \cdot 9 \cdot 9
\]

Calculating \( 9 \cdot 9 \):

\[
9 \cdot 9 = 81
\]

Then multiplying by 9 again:

\[
81 \cdot 9 = 729
\]

Thus, the numerical equivalent of \( 9^9 \cdot 9^{-6} \) is

\[
\boxed{729}
\]
Answered by GPT-4o mini
Apologies for misunderstanding your request. Let's calculate \( 9^9 \cdot 9^{-6} \) without using exponents.

First, we know from the previous steps:

\[
9^9 \cdot 9^{-6} = 9^3
\]

Now, we'll compute \( 9^3 \) step by step without using exponents:

1. \( 9 \times 9 = 81 \)
2. Then, \( 81 \times 9 \):

\[
81 \times 9 = 729
\]

So, without using exponents, the numerical equivalent of \( 9^9 \cdot 9^{-6} \) is

\[
\boxed{729}
\]

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