Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
In 1920, the record for a certain race was 46.6 sec. In 1980, it was 45.4 sec. Let R(t)= the record in the race and t = the num...Asked by Liz
In 1920, the record for a certain race was 46.6 sec. In 1980, it was 45.4 sec. Let R(t)= the record in the race and t = the number of years snce 1920.
a) Find a linear function that fits the data R(t) =
b) Use the function in (a) to predict the record in 2003 and in 2006.
2003 =
2006 =
c) Find the year when the record will be 46.68 sec.
a) Find a linear function that fits the data R(t) =
b) Use the function in (a) to predict the record in 2003 and in 2006.
2003 =
2006 =
c) Find the year when the record will be 46.68 sec.
Answers
Answered by
FredR
From 1920 to 1980 is 60 years. The record was shortened by 1.2 seconds. The slope of the line is the rise over the run, or:
-1.2/60
for t=0, R(t) = 46.6 so the y intercept is 46.6.
The format of a line is y = mx + b where m is the slope and b is the y intercept. So,
a) so the line would have the formula:
R(t) = -(1.2/60)t+46.6
b) substitute t=2003-1920 into part a and solve for R(t)
substitute t=2006-1920 into part a and solve for R(t)
c) substitute R(t) = 46.68 into part a and solve for t
-1.2/60
for t=0, R(t) = 46.6 so the y intercept is 46.6.
The format of a line is y = mx + b where m is the slope and b is the y intercept. So,
a) so the line would have the formula:
R(t) = -(1.2/60)t+46.6
b) substitute t=2003-1920 into part a and solve for R(t)
substitute t=2006-1920 into part a and solve for R(t)
c) substitute R(t) = 46.68 into part a and solve for t
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.