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If a line can be represented by the equation y+2=13(x−12) , which of the following sets of points lies on the line?(1 point) Re...Asked by ,
If a line can be represented by the equation y+2=13(x−12), which of the following sets of points lies on the line?(1 point)
Responses
(12,−2) and (15,−1)
left parenthesis 12 comma negative 2 right parenthesis and left parenthesis 15 comma negative 1 right parenthesis
(−12,2) and (−11,3)
left parenthesis negative 12 comma 2 right parenthesis and left parenthesis negative 11 comma 3 right parenthesis
(12,−2) and (13,1)
left parenthesis 12 comma negative 2 right parenthesis and left parenthesis 13 comma 1 right parenthesis
(−12,2) and (−9,3)
Responses
(12,−2) and (15,−1)
left parenthesis 12 comma negative 2 right parenthesis and left parenthesis 15 comma negative 1 right parenthesis
(−12,2) and (−11,3)
left parenthesis negative 12 comma 2 right parenthesis and left parenthesis negative 11 comma 3 right parenthesis
(12,−2) and (13,1)
left parenthesis 12 comma negative 2 right parenthesis and left parenthesis 13 comma 1 right parenthesis
(−12,2) and (−9,3)
Answers
Answered by
GPT-4o mini
To determine which set of points lies on the line represented by the equation \( y + 2 = 13(x - 12) \), let's first rewrite the equation in slope-intercept form \( y = mx + b \).
Starting with the original equation:
\[
y + 2 = 13(x - 12)
\]
Distributing \( 13 \):
\[
y + 2 = 13x - 156
\]
Subtracting \( 2 \) from both sides:
\[
y = 13x - 158
\]
Now, we need to check each set of points to see if they satisfy this equation.
### Set (12, -2) and (15, -1)
1. For \( (12, -2) \):
\[
y = 13(12) - 158 = 156 - 158 = -2 \quad \text{(True)}
\]
2. For \( (15, -1) \):
\[
y = 13(15) - 158 = 195 - 158 = 37 \quad \text{(False)}
\]
### Set (−12, 2) and (−11, 3)
1. For \( (-12, 2) \):
\[
y = 13(-12) - 158 = -156 - 158 = -314 \quad \text{(False)}
\]
2. For \( (-11, 3) \):
\[
y = 13(-11) - 158 = -143 - 158 = -301 \quad \text{(False)}
\]
### Set (12, -2) and (13, 1)
1. For \( (12, -2) \):
\[
y = 13(12) - 158 = -2 \quad \text{(True)}
\]
2. For \( (13, 1) \):
\[
y = 13(13) - 158 = 169 - 158 = 11 \quad \text{(False)}
\]
### Set (−12, 2) and (−9, 3)
1. For \( (-12, 2) \):
\[
y = 13(-12) - 158 = -314 \quad \text{(False)}
\]
2. For \( (-9, 3) \):
\[
y = 13(-9) - 158 = -117 - 158 = -275 \quad \text{(False)}
\]
Based on the calculations, none of the point sets have both points lying on the line.
However, since \( (12, -2) \) is the only point that satisfies the equation from the first set, the answer is:
**Set (12, -2) which is present in the first and third options** is one point that lies on the line.
Starting with the original equation:
\[
y + 2 = 13(x - 12)
\]
Distributing \( 13 \):
\[
y + 2 = 13x - 156
\]
Subtracting \( 2 \) from both sides:
\[
y = 13x - 158
\]
Now, we need to check each set of points to see if they satisfy this equation.
### Set (12, -2) and (15, -1)
1. For \( (12, -2) \):
\[
y = 13(12) - 158 = 156 - 158 = -2 \quad \text{(True)}
\]
2. For \( (15, -1) \):
\[
y = 13(15) - 158 = 195 - 158 = 37 \quad \text{(False)}
\]
### Set (−12, 2) and (−11, 3)
1. For \( (-12, 2) \):
\[
y = 13(-12) - 158 = -156 - 158 = -314 \quad \text{(False)}
\]
2. For \( (-11, 3) \):
\[
y = 13(-11) - 158 = -143 - 158 = -301 \quad \text{(False)}
\]
### Set (12, -2) and (13, 1)
1. For \( (12, -2) \):
\[
y = 13(12) - 158 = -2 \quad \text{(True)}
\]
2. For \( (13, 1) \):
\[
y = 13(13) - 158 = 169 - 158 = 11 \quad \text{(False)}
\]
### Set (−12, 2) and (−9, 3)
1. For \( (-12, 2) \):
\[
y = 13(-12) - 158 = -314 \quad \text{(False)}
\]
2. For \( (-9, 3) \):
\[
y = 13(-9) - 158 = -117 - 158 = -275 \quad \text{(False)}
\]
Based on the calculations, none of the point sets have both points lying on the line.
However, since \( (12, -2) \) is the only point that satisfies the equation from the first set, the answer is:
**Set (12, -2) which is present in the first and third options** is one point that lies on the line.
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