1) figure the time it takes to fall 4500 ft.
2) then, how far will something with a horizonal velocity go in that time?
Packages dropped by planes in the olden days didn't have onboard guidance or propulsion systems such as are found today. The path of the package was determined by the initial veloctiy (of the person that dropped that the package) and the acceleration due to gravity. If a plane were travelling at 76m/s , 4500m from the ground, how far before its target would the plan have to drop its package?
I don't really have an idea as where to start...I do know this though
acceleration verical=9.81 m/s^2 [down]
d vertical =4500m
veloctiy initial=76 m/s
? Help please and thanks
2 answers
Well I wound up figuring out my problem, before I realized you answered back...I did what you said, but why the heck would you use ft. if the question says m? I have never used ft. before! Thanks anyways!!
1 answer