Question

Use the periodic table to complete the activity.



























Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

Identify the acid, base, conjugate acid, and conjugate base in this reaction

(4 points)
H2Se is a(n)


H2O is a(n)

SeH– is a(n)

H3O+ is a(n)

Answer 1

In the reaction given:

\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]

we can identify the following:

1. **H2Se** is a(n) **acid**. It donates a proton (H⁺) to water in this reaction, forming the conjugate base.

2. **H2O** is a(n) **base**. It accepts a proton from hydrogen selenide, leading to the formation of the hydronium ion (H3O⁺).

3. **SeH⁻** is a(n) **conjugate base**. It is the species formed after H2Se donates a proton.

4. **H3O⁺** is a(n) **conjugate acid**. It is the species formed when water (acting as a base) accepts a proton.

To summarize:
- H2Se is an acid
- H2O is a base
- SeH⁻ is a conjugate base
- H3O⁺ is a conjugate acid