Kinetic energy is calculated using the formula:
\[ KE = \frac{1}{2}mv^2 \]
where \( m \) is the mass and \( v \) is the speed.
For the rabbit:
- Mass (\( m \)) = 4 kg
- Speed (\( v \)) = 5 m/s
Calculating the kinetic energy of the rabbit:
\[ KE_{\text{rabbit}} = \frac{1}{2} \times 4 , \text{kg} \times (5 , \text{m/s})^2 \] \[ KE_{\text{rabbit}} = \frac{1}{2} \times 4 \times 25 = 2 \times 25 = 50 , \text{Joules} \]
For the wildlife keeper:
- Mass (\( m \)) = 60 kg
- Speed (\( v \)) = 5 m/s
Calculating the kinetic energy of the wildlife keeper:
\[ KE_{\text{keeper}} = \frac{1}{2} \times 60 , \text{kg} \times (5 , \text{m/s})^2 \] \[ KE_{\text{keeper}} = \frac{1}{2} \times 60 \times 25 = 30 \times 25 = 750 , \text{Joules} \]
Comparing the two:
- Kinetic energy of the rabbit = 50 Joules
- Kinetic energy of the wildlife keeper = 750 Joules
The wildlife keeper has the greater kinetic energy due to their greater mass.
So the correct response is: The wildlife keeper because they have a greater mass.