A stock solution has a concentration of 12.4 M. What volume of stock solution would be needed to make 7.6 L of solution with a concentration of 4.4 M? (1 point)

Question

Responses

1.05 L
1.05 L

4.54 L
4.54 L

2.70 L
2.70 L

7.18 L

Answer 1

To find the volume of the stock solution needed to make a diluted solution, you can use the dilution formula:

\[ C_1 V_1 = C_2 V_2 \]

where:

• \( C_1 \) is the concentration of the stock solution (12.4 M),
• \( V_1 \) is the volume of the stock solution needed,
• \( C_2 \) is the concentration of the diluted solution (4.4 M),
• \( V_2 \) is the volume of the diluted solution (7.6 L).

Plugging in the values:

\[ 12.4, M \cdot V_1 = 4.4, M \cdot 7.6, L \]

Calculating \( 4.4, M \cdot 7.6, L \):

\[ 4.4 \times 7.6 = 33.44 , \text{moles} \]

Now we can rearrange the equation to solve for \( V_1 \):

\[ V_1 = \frac{33.44 , \text{moles}}{12.4 , M} \]

Calculating \( V_1 \):

\[ V_1 = \frac{33.44}{12.4} \approx 2.70 , L \]

Thus, the volume of stock solution needed is approximately 2.70 L.