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Asked by diane

there are 9 subjects, how many schedules of 5 classes are possible?
15 years ago

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Answered by FredR
Permutations of 9 objects taken 5 at a time =

9!/(9-5)!

where 4! = 4x3x2x1
and 9! = 9x8x7x6x5x4x3x2x1
15 years ago
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there are 9 subjects, how many schedules of 5 classes are possible?

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