Asked by diane
there are 9 subjects, how many schedules of 5 classes are possible?
Answers
Answered by
FredR
Permutations of 9 objects taken 5 at a time =
9!/(9-5)!
where 4! = 4x3x2x1
and 9! = 9x8x7x6x5x4x3x2x1
9!/(9-5)!
where 4! = 4x3x2x1
and 9! = 9x8x7x6x5x4x3x2x1
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