Question
Solve the system below using SUBSTITUTION. Show step-by-step work to earn credit. Use the Formula Editor x−−√ to type math or use the Image icon to upload a photo of your work.
2x+2y=38
y=x+3
2x+2y=38
y=x+3
Answers
Answered by
GPT-4o mini
To solve the system of equations using substitution, we have the following two equations:
1. \( 2x + 2y = 38 \)
2. \( y = x + 3 \)
### Step 1: Substitute \( y \) in the first equation
We can use the second equation to substitute \( y \) in the first equation.
Substituting \( y \) in equation 1:
\[
2x + 2(x + 3) = 38
\]
### Step 2: Simplify the equation
Now, we will simplify the left side of the equation:
\[
2x + 2x + 6 = 38
\]
Combine like terms:
\[
4x + 6 = 38
\]
### Step 3: Solve for \( x \)
Next, subtract 6 from both sides:
\[
4x = 38 - 6
\]
\[
4x = 32
\]
Now, divide both sides by 4:
\[
x = \frac{32}{4}
\]
\[
x = 8
\]
### Step 4: Substitute \( x \) back to find \( y \)
Now that we have \( x \), we can substitute \( x = 8 \) back into the second equation to find \( y \):
\[
y = x + 3
\]
\[
y = 8 + 3
\]
\[
y = 11
\]
### Step 5: Write the solution
The solution to the system of equations is:
\[
(x, y) = (8, 11)
\]
### Step 6: Verify the solution
To ensure the solution is correct, we can substitute \( x = 8 \) and \( y = 11 \) back into the original equations.
For the first equation:
\[
2(8) + 2(11) = 16 + 22 = 38 \quad \text{(True)}
\]
For the second equation:
\[
11 = 8 + 3 \quad \text{(True)}
\]
Both equations are satisfied, confirming that the solution is correct.
Thus, the solution is:
\[
\boxed{(8, 11)}
\]
1. \( 2x + 2y = 38 \)
2. \( y = x + 3 \)
### Step 1: Substitute \( y \) in the first equation
We can use the second equation to substitute \( y \) in the first equation.
Substituting \( y \) in equation 1:
\[
2x + 2(x + 3) = 38
\]
### Step 2: Simplify the equation
Now, we will simplify the left side of the equation:
\[
2x + 2x + 6 = 38
\]
Combine like terms:
\[
4x + 6 = 38
\]
### Step 3: Solve for \( x \)
Next, subtract 6 from both sides:
\[
4x = 38 - 6
\]
\[
4x = 32
\]
Now, divide both sides by 4:
\[
x = \frac{32}{4}
\]
\[
x = 8
\]
### Step 4: Substitute \( x \) back to find \( y \)
Now that we have \( x \), we can substitute \( x = 8 \) back into the second equation to find \( y \):
\[
y = x + 3
\]
\[
y = 8 + 3
\]
\[
y = 11
\]
### Step 5: Write the solution
The solution to the system of equations is:
\[
(x, y) = (8, 11)
\]
### Step 6: Verify the solution
To ensure the solution is correct, we can substitute \( x = 8 \) and \( y = 11 \) back into the original equations.
For the first equation:
\[
2(8) + 2(11) = 16 + 22 = 38 \quad \text{(True)}
\]
For the second equation:
\[
11 = 8 + 3 \quad \text{(True)}
\]
Both equations are satisfied, confirming that the solution is correct.
Thus, the solution is:
\[
\boxed{(8, 11)}
\]