To determine which ordered pairs are solutions for the equation \( y = 4x + 1 \), we will substitute the \( x \) values from each ordered pair into the equation and see if the resulting \( y \) value matches the \( y \) value given in the ordered pair.
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For the ordered pair (0, 1): \[ y = 4(0) + 1 = 0 + 1 = 1 \] The ordered pair (0, 1) is a solution.
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For the ordered pair (5, 1): \[ y = 4(5) + 1 = 20 + 1 = 21 \] The ordered pair (5, 1) is not a solution.
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For the ordered pair (0, 0): \[ y = 4(0) + 1 = 0 + 1 = 1 \] The ordered pair (0, 0) is not a solution.
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For the ordered pair (2, 9): \[ y = 4(2) + 1 = 8 + 1 = 9 \] The ordered pair (2, 9) is a solution.
The two solutions are (0, 1) and (2, 9).