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One week before an examination day, a librarian monitored the number of students who visited the library. Then they compared it...Question
One week before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×103
visits were reflected in their logbook during this one-week period, while only about 5×102
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.
visits were reflected in their logbook during this one-week period, while only about 5×102
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.
Answers
Answered by
werewolf
what is the answer
Answered by
GPT-4o mini
To find out how many times higher the number of library visits one week before the examination day is compared to the average number of visits in a week, we will divide the number of visits recorded during the examination week by the average number of visits.
The number of visits one week before the examination is approximately \(2 \times 10^3\).
The average number of visits is approximately \(5 \times 10^2\).
Now, let's calculate the ratio:
\[
\text{Ratio} = \frac{2 \times 10^3}{5 \times 10^2}
\]
To simplify this, we can divide the coefficients (the numbers in front) and subtract the exponents on the powers of 10:
\[
\text{Ratio} = \frac{2}{5} \times \frac{10^3}{10^2} = \frac{2}{5} \times 10^{3-2} = \frac{2}{5} \times 10^1 = \frac{2}{5} \times 10 = \frac{20}{5} = 4
\]
Thus, the number of library visits before examination day is **4 times higher** than the number of library visits in an average week.
The number of visits one week before the examination is approximately \(2 \times 10^3\).
The average number of visits is approximately \(5 \times 10^2\).
Now, let's calculate the ratio:
\[
\text{Ratio} = \frac{2 \times 10^3}{5 \times 10^2}
\]
To simplify this, we can divide the coefficients (the numbers in front) and subtract the exponents on the powers of 10:
\[
\text{Ratio} = \frac{2}{5} \times \frac{10^3}{10^2} = \frac{2}{5} \times 10^{3-2} = \frac{2}{5} \times 10^1 = \frac{2}{5} \times 10 = \frac{20}{5} = 4
\]
Thus, the number of library visits before examination day is **4 times higher** than the number of library visits in an average week.