Question

Nico is trying to write an equation in slope-intercept form for a line that passes through the point (1,2)
and has a slope of −12
. What is the y-intercept of this line, rounded to the nearest tenth? (1 point)

Answer 1

To find the equation of the line in slope-intercept form, which is given by the formula:

\[ y = mx + b \]

where \( m \) is the slope and \( b \) is the y-intercept, we can use the point (1, 2) to substitute into the equation along with the given slope of -12.

1. Substitute the slope into the equation:

\[ y = -12x + b \]

2. Now, substitute the point (1, 2) into the equation. Here, \( x = 1 \) and \( y = 2 \):

\[ 2 = -12(1) + b \]

3. Simplify the equation:

\[ 2 = -12 + b \]

4. Solve for \( b \):

\[ b = 2 + 12 \]

\[ b = 14 \]

Now that we have the y-intercept \( b = 14 \), rounded to the nearest tenth, the y-intercept is:

**14.0**