Question

A stock solution has a concentration of 12.4 M. What volume of stock solution would be needed to make 7.6 L of solution with a concentration of 4.4 M? (1 point)
Responses

1.05 L
1.05 L

7.18 L
7.18 L

4.54 L
4.54 L

2.70 L
2.70 L

Answer 1

To determine the volume of the stock solution needed to make a diluted solution, you can use the dilution equation:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \(C_1\) = concentration of the stock solution (12.4 M)
- \(V_1\) = volume of the stock solution to find
- \(C_2\) = concentration of the diluted solution (4.4 M)
- \(V_2\) = volume of the diluted solution (7.6 L)

Rearranging the equation to solve for \(V_1\):

\[
V_1 = \frac{C_2 V_2}{C_1}
\]

Substituting in the known values:

\[
V_1 = \frac{(4.4 \, \text{M}) \times (7.6 \, \text{L})}{12.4 \, \text{M}}
\]

Calculating this:

\[
V_1 = \frac{33.44}{12.4} \approx 2.7 \, \text{L}
\]

The required volume of the stock solution is approximately **2.70 L**.

Therefore, the correct response is:

**2.70 L**