Question 1

Question

A)Which substance is an example of a nonpolar compound?(1 point)
Responses

sugar
sugar

vegetable oil
vegetable oil

water
water

food coloring
food coloring
Question 2
A)
Use the graph to answer the question.

A line graph depicts the variation of the solubility of oxygen in water with temperature. The vertical axis is labeled, solubility (grams of oxygen per 100 g H2O), and ranges from 0.0010 to 0.0070 in increments of 0.0010. The horizontal axis is labeled, temperature (degree C), and ranges from 0 to 100 in increments of 10. The line for solubility slopes downward from a point on the vertical axis just below 0.0070, first with a higher slope and then with a smaller slope and moves to the point (100, 0) on the horizontal axis.

Which statement is the best explanation for the graph?

(1 point)
Responses

As temperature rises, gas particles are moving faster and may leave the solution.
As temperature rises, gas particles are moving faster and may leave the solution.

As temperature rises, gas particles are moving faster and are more likely to enter the solution.
As temperature rises, gas particles are moving faster and are more likely to enter the solution.

As temperature rises, the space between liquid particles decreases, leaving less room for gas particles.
As temperature rises, the space between liquid particles decreases, leaving less room for gas particles.

As temperature rises, the space between liquid particles increases, allowing more room for gas particles.
As temperature rises, the space between liquid particles increases, allowing more room for gas particles.
Question 3
A)After which action would the concentration of a solution remain constant?(1 point)
Responses

adding solute to the solution
adding solute to the solution

adding water to the solution
adding water to the solution

evaporating water from the container
evaporating water from the container

removing solution from the container
removing solution from the container
Question 4
A)A scientist has 500 mL of a 2.1 M stock solution. She dilutes the solution, and the volume of the solution after the dilution is 3.25 L. What is the molarity (M) of the diluted solution? (1 point)
Responses

0.32 M
0.32 M

0.01 M
0.01 M

13.65 M
13.65 M

323.08 M
323.08 M
Question 5
A)A stock solution has a concentration of 12.4 M. What volume of stock solution would be needed to make 7.6 L of solution with a concentration of 4.4 M? (1 point)
Responses

1.05 L
1.05 L

4.54 L
4.54 L

7.18 L

Answer 1

Here are the answers to your questions:

Question 1:
A) Which substance is an example of a nonpolar compound?
Response: vegetable oil

Question 2:
Which statement is the best explanation for the graph?
Response: As temperature rises, gas particles are moving faster and may leave the solution.

Question 3:
After which action would the concentration of a solution remain constant?
Response: adding solute to the solution

Question 4:
A scientist has 500 mL of a 2.1 M stock solution. She dilutes the solution, and the volume of the solution after the dilution is 3.25 L. What is the molarity (M) of the diluted solution?
Response: 0.32 M
(Calculation: M1V1 = M2V2 -> (2.1 M)(0.5 L) = M2(3.25 L) => M2 = (1.05)/3.25 = 0.32 M)

Question 5:
A stock solution has a concentration of 12.4 M. What volume of stock solution would be needed to make 7.6 L of solution with a concentration of 4.4 M?
Response: 2.28 L
(Calculation: M1V1 = M2V2 -> 12.4 M * V1 = 4.4 M * 7.6 L => V1 = (4.4 M * 7.6 L)/12.4 M = 2.14 L)

Please check these answers as I don't have the specific values from the stock solution question calculation; note that the last value is based on estimating a process to match your earlier provided options.