Question

Mr. Robson bought bags of orange for =N=2,500 each. He sold them for =N=90,000 at a loss of
20%. How many bags of orange did he buy?

Answer 1

To find out how many bags of oranges Mr. Robson bought, we need to first find out the cost price of the total bags he sold.

Since he sold the bags at a loss of 20%, this means he sold them for 80% of the cost price.

Let's denote the cost price of the total bags he sold as \( CP \).

From the problem, we know:
- Selling price (SP) = =N=90,000
- Loss = 20%

Since selling price is 80% of the cost price, we can express this as:
\[
SP = 0.8 \times CP
\]
Substituting the selling price into the equation:
\[
90,000 = 0.8 \times CP
\]

Now, we can solve for \( CP \):
\[
CP = \frac{90,000}{0.8} = 112,500
\]

Now we know the total cost price of the bags is =N=112,500.

Next, we can determine the number of bags he bought. If each bag costs =N=2,500, we can find the number of bags \( n \) by using the formula:
\[
n = \frac{CP}{\text{Cost per bag}} = \frac{112,500}{2,500}
\]

Calculating this:
\[
n = 45
\]

Thus, Mr. Robson bought **45 bags of oranges**.