consider the expression 47/3 + 121squared. will the sum of the two rational numbers produce a rational or irrational number? find the sum and explain your reasoning in 1 small sentence

The expression \( \frac{47}{3} + 121^2 \) results in \( \frac{47}{3} + 14641 \), which is a sum of two rational numbers; hence, the result is also rational.

To find the sum:
\[
121^2 = 14641 \\
\frac{47}{3} + 14641 = \frac{47}{3} + \frac{14641 \times 3}{3} = \frac{47 + 43923}{3} = \frac{43970}{3}
\]
Thus, the sum is \( \frac{43970}{3} \), which is rational.