What is the solution set for the value of k in the

equation 7+2𝑘2=25

1 answer

To find the value of \( k \) in the equation \( 7 + 2k^2 = 25 \), we can follow these steps:

  1. Start with the equation: \[ 7 + 2k^2 = 25 \]

  2. Subtract 7 from both sides: \[ 2k^2 = 25 - 7 \] \[ 2k^2 = 18 \]

  3. Divide both sides by 2: \[ k^2 = \frac{18}{2} \] \[ k^2 = 9 \]

  4. Take the square root of both sides: \[ k = \pm 3 \]

Thus, the solution set for \( k \) is: \[ k = 3 \quad \text{or} \quad k = -3 \]

So the solution set is \( { 3, -3 } \).