Kinetic energy is calculated using the formula:
\[ KE = \frac{1}{2} mv^2 \]
where \( m \) is the mass and \( v \) is the velocity.
For the wildlife keeper (mass = 60 kg, speed = 5 m/s):
\[ KE_{keeper} = \frac{1}{2} \times 60 , \text{kg} \times (5 , \text{m/s})^2 \] \[ KE_{keeper} = \frac{1}{2} \times 60 \times 25 \] \[ KE_{keeper} = \frac{1}{2} \times 1500 \] \[ KE_{keeper} = 750 , \text{Joules} \]
For the rabbit (mass = 4 kg, speed = 5 m/s):
\[ KE_{rabbit} = \frac{1}{2} \times 4 , \text{kg} \times (5 , \text{m/s})^2 \] \[ KE_{rabbit} = \frac{1}{2} \times 4 \times 25 \] \[ KE_{rabbit} = \frac{1}{2} \times 100 \] \[ KE_{rabbit} = 50 , \text{Joules} \]
Comparing the two kinetic energies:
- Kinetic energy of the wildlife keeper: 750 Joules
- Kinetic energy of the rabbit: 50 Joules
Therefore, the wildlife keeper has the greater kinetic energy.