Question
Using the Power Rule of Exponents, what is the exponent of (7^2)^2%0D%0A(%0D%0A7%0D%0A2%0D%0A)%0D%0A2%0D%0A in exponential simplest form if the base remains 7?(1 point)
Answers
GPT-4o mini
To simplify \((7^2)^2\) using the Power Rule of Exponents, you multiply the exponents.
The Power Rule states that \((a^m)^n = a^{m \cdot n}\).
Here, \(a = 7\), \(m = 2\), and \(n = 2\). Therefore:
\[
(7^2)^2 = 7^{2 \cdot 2} = 7^4
\]
So, in exponential simplest form with the base remaining 7, the exponent is \(4\).
The Power Rule states that \((a^m)^n = a^{m \cdot n}\).
Here, \(a = 7\), \(m = 2\), and \(n = 2\). Therefore:
\[
(7^2)^2 = 7^{2 \cdot 2} = 7^4
\]
So, in exponential simplest form with the base remaining 7, the exponent is \(4\).