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3x - 2y = -4
x - 5y = 3
Review the graphs of a system of two linear equations in two variables: x - 5y = 7 and 3x - 2y = -4. Find the solution to both equations.
The intersection point is (__).
3x - 2y = -4
x - 5y = 3
Review the graphs of a system of two linear equations in two variables: x - 5y = 7 and 3x - 2y = -4. Find the solution to both equations.
The intersection point is (__).
Answers
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Answered by
GPT-4o mini
To find the solution to the system of linear equations given by:
1. \( 3x - 2y = -4 \)
2. \( x - 5y = 3 \)
we can solve the equations using substitution or elimination. In this case, let's use substitution.
First, solve the second equation for \( x \):
\[
x = 5y + 3
\]
Now, substitute this expression for \( x \) into the first equation:
\[
3(5y + 3) - 2y = -4
\]
Expand and simplify:
\[
15y + 9 - 2y = -4
\]
Combine like terms:
\[
13y + 9 = -4
\]
Subtract 9 from both sides:
\[
13y = -4 - 9
\]
\[
13y = -13
\]
Now, divide by 13:
\[
y = -1
\]
Next, substitute \( y = -1 \) back into the equation \( x = 5y + 3 \):
\[
x = 5(-1) + 3
\]
\[
x = -5 + 3
\]
\[
x = -2
\]
Thus, the solution to the system is \( (x, y) = (-2, -1) \).
So, the intersection point is **(-2, -1)**.
1. \( 3x - 2y = -4 \)
2. \( x - 5y = 3 \)
we can solve the equations using substitution or elimination. In this case, let's use substitution.
First, solve the second equation for \( x \):
\[
x = 5y + 3
\]
Now, substitute this expression for \( x \) into the first equation:
\[
3(5y + 3) - 2y = -4
\]
Expand and simplify:
\[
15y + 9 - 2y = -4
\]
Combine like terms:
\[
13y + 9 = -4
\]
Subtract 9 from both sides:
\[
13y = -4 - 9
\]
\[
13y = -13
\]
Now, divide by 13:
\[
y = -1
\]
Next, substitute \( y = -1 \) back into the equation \( x = 5y + 3 \):
\[
x = 5(-1) + 3
\]
\[
x = -5 + 3
\]
\[
x = -2
\]
Thus, the solution to the system is \( (x, y) = (-2, -1) \).
So, the intersection point is **(-2, -1)**.
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